Question

3a²bc + 6ab²c + 9abc²
Factorise

Answer 1

Step-by-step explanation:

3abc ( a + 2 b + 3 c)

Pls mark it as the brainliest answer

Answer 2

3a²bc + 6ab²c + 9abc² = 3abc (a + 2b + 3c)

Step-by-step explanation:

3a²bc + 6ab²c + 9abc²

Let's take the common factor 3 outside the bracket, we get 3 (a²bc + 2ab²c + 3abc²)

We also find abc is common, so let's take that out of the bracket as well.  We get 3abc (a + 2b + 3c).

The factors of the equation 3a²bc + 6ab²c + 9abc² are 3abc and (a + 2b + 3c).