3a²bc + 6ab²c + 9abc²
Factorise
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Answered by
3
Step-by-step explanation:
3abc ( a + 2 b + 3 c)
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Answered by
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3a²bc + 6ab²c + 9abc² = 3abc (a + 2b + 3c)
Step-by-step explanation:
3a²bc + 6ab²c + 9abc²
Let's take the common factor 3 outside the bracket, we get 3 (a²bc + 2ab²c + 3abc²)
We also find abc is common, so let's take that out of the bracket as well. We get 3abc (a + 2b + 3c).
The factors of the equation 3a²bc + 6ab²c + 9abc² are 3abc and (a + 2b + 3c).
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