Question

3a²x² +8 abx + 4b² = 0
​

Answer 1

Step-by-step explanation:

3a²x²+8abx+4b²= 0

since, 8ab = 6ab+2ab

and

6ab×2ab= 12a²b²= coeff of x²× const term

=> 3a²x²+6abx+2abx+4b²=0

=> 3ax( ax+2b) +2b( ax+2b) =0

=> (ax+2b) ( 3ax+2b) = 0

=> if 3ax+2b ≠ 0 then ax+2b= 0

=> x= -2b/a

=> if ax+2b≠0 => 3ax+2b=0.

=> x= -2b/3a

Answer => x= -2b/a ,-2b/3a

We can solve this quadratic eqn ,using

quadratic formula given by a great Indian mathematician Mr.

" sridharacharya" ji.

x= [-b±√(b²-4ac) ] / 2a

Answer 2

Step-by-step explanation:

$3a {}^{2}2x {}^{2} 2 + 6abx + 2abx + 4b {}^{2} 2 \\ 3ax(ax + 2b) + 2b(ax + ab) \\ (3ax + 2b)(ax + 2b)$