Question

3a³+4a-3
(factorisation)​

Answer 1

Answer:

Take a = (1 / 2). So, [8*(1 / 8) + 4*(1 / 2) - 3] = 0.

So, (2a - 1) will be a factor.

8a^3 + 4a - 3

= (2a - 1)*(4a^2 + 2a + 3)

Now, concentrate on (4a^2 + 2a + 3).

Since, {(2)^2} < {4*4*3}; so, there is no real root for a in (4a^2 + 2a + 3).

So, (2a - 1)*(4a^2 + 2a + 3) is the answer.

Step-by-step explanation:

...Hope this will help u...