Question

(3a4 – 2a2 + 5a – 10) – (2a4 + 4a2 + 5a – 2)

Answer 1

3a4-2a2+5a-10-2a4-4a2-5a+2=a4-6a2-8

Answer 2

$\huge\underline\mathfrak{Solution}$

$\textbf{Step -By-Step-Solution}$

$3a^{4}-2a^{2}+5{a}-10\\-2a^{4}-4a{2}-5a+2$
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$a^{4}-6a{2}-0a-8$

so,eq become

$a^{4}-6a^{2}-8=0$