Math, asked by 3170266, 4 months ago

(3ab^2c)*(a^2c^3)*(-7),a=1,b=-1,c=2

Answers

Answered by TariniKeerthi
0

Answer:

-336

Step-by-step explanation:

3ab^2c)*(a^2c^3)*(-7)

[3*1*(-1)^2*2] * [1^2*2^3] * [-7]

[3*1*1*2] * [1*8] * -7

6*8*(-7)

= -336

Hope it helps you :)

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