Question

(3abc-6ab+7b) multiplied by (2a-1) find its value if a=1 b=2 c=1​

Answer 1

Answer:

a=1

b=2

c=1

then,

3abc-6ab+7b×(2a-1)

(3×1×2×1)-(6×1×2)+(7×2)×(2×1-1)

6-12+14×(2-1)

6-12+14×1

6-12+14

6-26

-20