Question

3and -3 are the zeros of the polynomial xquadrate +xcube -11xsquare -9x-18

Answer 1

P(x)=x^4+x^3-11x^2-9x-18

P(3)=(3)^4+(3)^3-11(3)^2-9(3)-18

P(3)=81+27-11(9)-27-18

P(3)=81+27-99-27-18

P(3)=-36

P(x)=x^4+x^3-11x^2-9x-18

P(-3)=(-3)^4+(-3)^3-11(-3)^2-9(-3)-18

P(-3)=81-27-11(9)+28-18

P(-3)=81-27-99+28-18

P(-3)=-35

3,-3 are not the zeroes of the cubic polynomial

xquadrate +xcube -11xsquare -9x-18

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