Question

-3and2

$\alpha + \beta = - 3 = \frac{ - b}{a} \\ \alpha \beta = 2 = \frac{c}{a.} \\ a = 1 \: b = 3 \: c = 2 \\ ans \\ x {}^{2} + 3x + 2$

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Answer 1

Correct question

If the sum and product of roots of an equation are -3,2.Then find the equation

Given

$\alpha+\beta=-3$

$\alpha\times\beta=2$

To find

The quadratic equation

Explanation

If the sum and product of roots of an equation are given

then the formula of the quadratic equation formed is

$\boxed{ \bf \: {x}^{2} - ( \alpha + \beta ) x + \alpha \beta }$

Applying this formula

$= > {x}^{2} - ( - 3)x + 2 \\ \\ = > \huge \boxed{ {x}^{2} + 3x + 2}$

Therefore the quadratic equation is

x²+3x+2

Some more information

To find the roots of a quadratic equation

the below formula can be used.

$\sf x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

Answer 2

Answer:

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Step-by-step explanation:

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