Math, asked by rahul1784738, 10 months ago

3ax^2+17ax+10a factories of the following expressions​

Answers

Answered by itsrehan07
1

Answer:

3ax {}^{2}  + 17ax + 10a = 0 \\ 3ax {}^{2}  + 15ax + 2ax + 10a = 0 \\ 3ax(x + 5) + 2a(x + 5) = 0 \\ (x + 5)(3ax + 2a) = 0 \\ x + 5 = 0 \: or \: 3ax + 2a = 0 \\ x =  - 5 \: or \: x =   \frac{ - 2}{3}

Answered by adityaandpranjalsing
0

Answer:

(3ax+2a) (x+5)

Step-by-step explanation:

3ax^2+17ax+10a

3ax^2+15ax+2ax+10a

3ax(x+5)+2a(x+5)

(3ax+2a) (x+5)

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