3b=a+c,2c=a+b,a+b+c=8,a=?
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The value of a is 10/3
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3b+ 2c = a+c+a+b
2b +c -2a =0
2(b-a) = -c
2(a-b) = c
a+b+c = 8
a+b + 2a-2b = 8
3a -b = 8
Also a+ b= 2c = 4(a-b)
a+ b = 4a - 4b
-3a +5b =0
and 3a-b=8
4b = 8
b=2
now -3a+ 10 =0
a= 10/3
2b +c -2a =0
2(b-a) = -c
2(a-b) = c
a+b+c = 8
a+b + 2a-2b = 8
3a -b = 8
Also a+ b= 2c = 4(a-b)
a+ b = 4a - 4b
-3a +5b =0
and 3a-b=8
4b = 8
b=2
now -3a+ 10 =0
a= 10/3
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