Question

3c^5 -18^4 -48c^3 factorise by splitting

Answer 1

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$\:\:\:\:\:\:3c {}^{5} - 18c {}^{4} - 48c {}^{3}$

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$= 3c {}^{3} (c {}^{2} - 6c - 16) \\ \\ = 3c {}^{3} [c {}^{2} - (8 - 2)c - 16] \\ \\ = 3c {2}^{2} (c {}^{2} - 8c + 2c - 16) \\ \\ = 3c {}^{3} [c(c - 8) + 2( c - 8)] \\ \\ = 3c {}^{3} (c - 8)(c + 2)$

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