3c^5-18c^4-48c^3 factorise
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3 c^5 - 18c^4 - 48c^3
= 3c^3 ( c^2 - 6c - 16)
= (3c^3) [ c^2 - 8c + 2c - 16]
= (3c^3) [ c(c - 8) + 2(c - 8)]
= (3c^3) (c - 8)(c +2)
= 3c^3 ( c^2 - 6c - 16)
= (3c^3) [ c^2 - 8c + 2c - 16]
= (3c^3) [ c(c - 8) + 2(c - 8)]
= (3c^3) (c - 8)(c +2)
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here is your answer...
thankyou
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