3C²— 20C +25=0 equation solve
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Answer:
(c-5)(3c-5)
Step-by-step explanation:
1. let a=3,b=(-20),c=25
2. product=ac=3×25=75
3. sum=b=(-20)
4.3c²-15c-5c+25
5.3c(c-5)-5(c-5)
6.(c-5)(3c-5)
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