Question

3cos^-1(-1\√2)+4tan^-1(-1)​

Answer 1

Step-by-step explanation:

cos

−1

(−

2

1

)−sin

−1

(

2

1

)+3cos

−1

(−

2

1

)−4tan

−1

(−1)

=π−cos

−1

(−

2

1

)−2sin

−1

(

2

1

)+3[π−cos

−1

(−

2

1

)]+4tan

−1

(−1)

=π−

3

π

−

6

2π

+3(π−

4

π

)+

4

4π

=

12

43π