3cos^-1(-1\√2)+4tan^-1(-1)
Answers
Answered by
1
Step-by-step explanation:
cos
−1
(−
2
1
)−sin
−1
(
2
1
)+3cos
−1
(−
2
1
)−4tan
−1
(−1)
=π−cos
−1
(−
2
1
)−2sin
−1
(
2
1
)+3[π−cos
−1
(−
2
1
)]+4tan
−1
(−1)
=π−
3
π
−
6
2π
+3(π−
4
π
)+
4
4π
=
12
43π
Similar questions