Question

3cos A - 4sinA =2cosA+ sinA
Find tan A

Answer 1

3sinA+ 4cosA=5
squaring both sides,
9sin2A + 16cos2B + 24sinAcosA = 25........................(1)
4sinA - 3cosA = x
squaring both sides,
16sin^2A + 9cos^2A – 24sinAcosA = x^2 …............(2)
Add eqns. 1) and 2)
9 + 16 = x^2
x^2 = 25
x = +5 and x = -5

Answer 2

Hi Dheeren

3cosA-4sinA=2cosA+sinA

3cosA-2cosA=sinA+4sinA

cosA=5sinA

1=5sinA/cosA

1/5=sinA/cosA

1/5=tanA

Hence tanA=1/5

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