3cos theeta =5sin theeta then find the value of 5sin theeta- 2sec qube theeta +2cos theeta ÷5sin theeta +2sec qube theeta- 2cos theeta
Answers
Answered by
0
Answer:
3cosQ=5sinQ
5sinQ-2cos+2cosQ÷5sinQ+2secQ-2secQ
5sin÷5sinQ
1
Similar questions