Question

3cosA=2sinA,then find the value of 4sinA-3cosA/2sinA+6cosA

Answer 1

3cosA=2sinA
tanA= 3/2
Therefore, by drawing a right triangle..
We can see that the perpendicular is 3 and the base is 2, therefore the hypotenuse is √13.
(By Pythagoras theorem)
Therefore, sinA = P/H
= 3/√13
cosA = B/H
= 2/√13
By substituting the values of sinA and cosA in the given equation, you can get the answer automatically.
Thank you.