√3costheta+sintheta=√2
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theata= π/6-cosinverse(✓2)
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both side dived by 2
then ,
√3/2 cos theta+1/√2sin theta =√2/2
cos30 cos theta+ sin30 sin theta= 1/√2
sin(30+theta)=sin 45
30+ theta=45
there= 15
then ,
√3/2 cos theta+1/√2sin theta =√2/2
cos30 cos theta+ sin30 sin theta= 1/√2
sin(30+theta)=sin 45
30+ theta=45
there= 15
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