3cosx+4sinx=4then the value of 3cosx-4sinx is
Answers
Answered by
3
hope this ans is helpfull to u
Attachments:
amit546:
iska answer 3or - 3 lana h
Answered by
5
heya...!!!
(3cosx + 4sinx)² = 4²
= > 9cos²x + 16sin²x + 24sinx = 16-----(1)
now,
(3cosx - 4sinx) = k(say)
(3cosx - 4sinx)² = k²
=> 9cos²x + 16sin²x - 24sinxcosx = k²-------(1)
adding--(1) and --(2)
we get,
9cos²x + 16sin²x + 24sinxcosx + 9cos²x + 16sin²x - 24sinxcosx = k² + 16
=> 18cos²x + 32sin²x = k² + 16
=> 18(1 - sin²x) + 32sin²x = k² + 16
=> 18 - 18sin²x + 32sin²x = k² + 16
=> 18 - 16 + 32sin²x - 18sin²x = k²
=> 2 + 14 = k²
=> 16 = k²
=> k = 4
HENCE,
k = 4 = (3cosx - 4sinx)
(3cosx + 4sinx)² = 4²
= > 9cos²x + 16sin²x + 24sinx = 16-----(1)
now,
(3cosx - 4sinx) = k(say)
(3cosx - 4sinx)² = k²
=> 9cos²x + 16sin²x - 24sinxcosx = k²-------(1)
adding--(1) and --(2)
we get,
9cos²x + 16sin²x + 24sinxcosx + 9cos²x + 16sin²x - 24sinxcosx = k² + 16
=> 18cos²x + 32sin²x = k² + 16
=> 18(1 - sin²x) + 32sin²x = k² + 16
=> 18 - 18sin²x + 32sin²x = k² + 16
=> 18 - 16 + 32sin²x - 18sin²x = k²
=> 2 + 14 = k²
=> 16 = k²
=> k = 4
HENCE,
k = 4 = (3cosx - 4sinx)
sir iska answer 3 or - 3 lana h
but it is not possible
may be your answer is wrong
ok
Similar questions