√3cot 2Φ-3=0 find the value of theta
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√3cot 2∅ - 3 = 0
√3 cot 2∅ = 3
cot 2∅ = 3/√3
cot 2∅ = √3
cot 2∅= cot 30
2∅ = 30
∅ = 30/2
∅ = 15°
√3 cot 2∅ = 3
cot 2∅ = 3/√3
cot 2∅ = √3
cot 2∅= cot 30
2∅ = 30
∅ = 30/2
∅ = 15°
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1
Here is your answer
✓3 cot2¢ - 3 = 0
✓3 cot2¢= 3
cot2¢ =3/✓3
cot2¢ = ✓3
cot2¢ = cot30°
2¢ = 30°
¢ = 30°/2 = 15°
Hope it helps you ^_^
Mark as brainliest
✓3 cot2¢ - 3 = 0
✓3 cot2¢= 3
cot2¢ =3/✓3
cot2¢ = ✓3
cot2¢ = cot30°
2¢ = 30°
¢ = 30°/2 = 15°
Hope it helps you ^_^
Mark as brainliest
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