Question

3cot theta =2. show that 4sin theta -3cos theta /2sin theta +6cos theta =1/3​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

1/3.

Step-by-step explanation:

Given,

cot theta =2/3.

Now, by pythagoras theorem, we have,

AC^2 = AB^2 + BC^2

AC^2 = 9 + 4

AC = root 13.

Now,

4 sin theta- 3 cos theta/ 2 sin theta + 6 cos theta.

= 4× 3 / root 13 - 3× 2/ root 13 by 2× 3 / root 13 + 6× 2/ root 13

= 6 / root 13 by 18/ root 13

= 1/3.