3cotA=4 find the value of cosecsquareA+11cosecsquare-1
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in triangle ABC, let b be equal to 90 degrees, ∴ AC is hypotenuse
3 cot A = 4
⇒cot A = 4/3
and
cot θ = adj/opp
∴AB = 4
BC = 3
AC² = 4² + 3² (pythagoras thm.)
= 25
AC = 5
cosec θ = hypo/adj
∴cosec A = AC/AB = 5/4
cosec² A + 11cosec² A -1 = (5/4)² + 11(5/4)² - 1
= 25/16 + 275/16 - 16/16
= 316/16
= 79/4
3 cot A = 4
⇒cot A = 4/3
and
cot θ = adj/opp
∴AB = 4
BC = 3
AC² = 4² + 3² (pythagoras thm.)
= 25
AC = 5
cosec θ = hypo/adj
∴cosec A = AC/AB = 5/4
cosec² A + 11cosec² A -1 = (5/4)² + 11(5/4)² - 1
= 25/16 + 275/16 - 16/16
= 316/16
= 79/4
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