3cotA=4 then 5sinA+3cosA÷5sinA-3cosA
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3cotA=4
cotA=4/3
H²=P²+B² => H²= (3k)²+(4k)² = 9k²+16k²= 25k²
H= 5k
sinA= P/H = 3k/5k =3/5
cosA= B/H = 4k/5k = 4/5
= 5sinA+3cosA/5sinA-3cosA
= 5×3/5 + 3×4/5 / 5×3/5 - 3×4/5
= 3+ 12/5 / 3- 12/5
= 15+12/5 / 15-12/5
= 27/5 / 3/5
= 27/5 × 5/3 = 9
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