Math, asked by sandeepsharan7218, 10 months ago

3cotx-5e^x +3logx-4/x^3/4 derivative

Answers

Answered by yashpal88
2

Step-by-step explanation:

let P = 3cotx - 5e^x + 3logx - 4/x^3/4

so P = 3cotx - 5e^x + 3logx - 4x^-3/4

therefore dP/dx = -3 cosec²x -5e^x +3/x + 3/x^7/4

this is the answer to your question.

Mark it as brainliest if you find it helpful

thank you.

Similar questions