Question

3cu + 8hno3 = 3cu(no3)2 + 4h2o + 2no find the mass of copper needed to react with 63g of hno3 and find the volume of nitric oxide collected at the same time.

Answer 1

Explanation:

3 Moles of Cu reacts with 8 moles of HNO3.

1 mole of HNO3 = 1 + 14 + 48 = 63 g

1 mole of HNO3 requires 3/8 mole of Cu.

= 189/8 g = 23.625 g

1 mole of Cu liberates 2 moles of NO.

3/8 moles of Cu liberates 3/4 moles of NO.

= 16.8 L.

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