-3एक्स²+एक्स⁴+एक्स ⁵की घात क्या है
Answers
Step-by-step explanation:
Explanation:
Question
A force of 5 N acting on a body at an Angle of 30° with horizontal direction displaces it horizontally through a distance of 6 m Calculate the work done.
\rule{250}{2}
We know : Work Done = Fs × cosθ
Where
F = Force
s = Displacement
θ = Angle Formed
Work Done = Fs × cosθ
⇒ Work Done = F × s × cosθ
⇒ Work Done = 5 × 6 × cosθ
⇒ Work Done = 30 × cosθ
Note : We will Have θ = 30° as it is given Angle Formed is equal to 30°
⇒ Work Done = 30 × cos 30°
⇒ Work Done = 30 × \rm{\dfrac{\sqrt{3}}{2}}
2
3
⇒ Work Done = 15 × √3
⇒ Work Done = 15 × 1.732
⇒ Work Done = 25.98 JExplanation:
Question
A force of 5 N acting on a body at an Angle of 30° with horizontal direction displaces it horizontally through a distance of 6 m Calculate the work done.
\rule{250}{2}
We know : Work Done = Fs × cosθ
Where
F = Force
s = Displacement
θ = Angle Formed
Work Done = Fs × cosθ
⇒ Work Done = F × s × cosθ
⇒ Work Done = 5 × 6 × cosθ
⇒ Work Done = 30 × cosθ
Note : We will Have θ = 30° as it is given Angle Formed is equal to 30°
⇒ Work Done = 30 × cos 30°
⇒ Work Done = 30 × \rm{\dfrac{\sqrt{3}}{2}}
2
3
⇒ Work Done = 15 × √3
⇒ Work Done = 15 × 1.732
⇒ Work Done = 25.98 J
Answer:
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