Question

3g of a solute are dissolved in 30g of water to form a saturated solution at 298k . Calculate the solubility of the solute at this temperature​

Answer 1

Answer:

10%

Explanation:

Amt. of solute = 3 g

Amt. of solvent (water) = 30 g

Solubility(at 298 K) = $\frac{Amt. of solute}{Amt. of solvent}$ = $\frac{3g}{30g} * 100$

Solubility(at 298 K) = 10%

Answer 2

Answer:

⟹ To calculate the solubility of any solute,we just have to divide the mass of the solvent with the mass of the solute(with a percentage multiplication)

⟹ So the solubility of the saturated solution mentioned in the question;

=Mass of solvent/Mass of water×100

=3/30×100

=10

So the solubility of the saturated solution mentioned in the question is almost 10. (Answer)