Question

3g of mg is burnt with xg of o2 find x during the formation of mgo​

Answer 1

Given - Weight of magnesium - 3 gram

Find - Weight of oxygen gas required for reaction.

Solution - The chemical reaction between given substrates will be as follows -

2Mg + O2 --> 2MgO

In the reaction, 2 moles of magnesium react with 1 mole of oxygen.

Number of moles of magnesium - 3/24

Number of moles of magnesium - 1/8 - 0.125

As per reaction, 2 moles of magnesium react with 1 mole of oxygen.

So, 0.125 moles of magnesium will react with -(1/2)*0.125

Moles of oxygen - 0.0625

Weight of oxygen - 0.0625*32

Weight of oxygen - 2 gram.

Hence, the value of X in the question is 2.

Answer 2

Answer:

2 grams of Oxygen

Explanation:

In order to calculate the amount of one reactant in a chemical reaction, it is important to first write down its balanced chemical equation. For the given reaction, equation is;

2Mg + 02 == 2MgO

Now here we can see that two moles of Mg and one mole of oxygen are required.

We are given 3 grm of Mg means 0.125 moles (3/24)

Now required moles of oxygen will be = 0.125/2 = 0.0625

Mass of oxygen = 32 x 0.0625 = 2 grams