Question

3gm of h2 react with 29 gm of o2 to give water. The maximum amount of h2o formed is

Answer 1

Answer:

It is about 54.54 ..................

Answer 2

Answer:

3g of hydrogen will be the limiting reagent.

2H2+O2 ------->2H2O

From the above equation it is clear that 2 mole H2 react with 1 mole O2

Molar mass of H2 = 2g

Molar mass of O2= 32 g

This implies,

4 g H2 react with 32 g O2

3 g H2 reacts with = (32/4) x 3g of O2 gas

= 24 g

As the given amount of O2 is more than required therefore O2 is excess reagent and H2 is limiting reagent.

B.

2 mole of hydrogen gas reacts to form 2 mole of water molecule therefore,

4 g of H2 produces = 36 g of water

So the amount of H2O produced by 3 g H2 = (36/4) x 3

= 27 g

Hence, 27 g of water will be produced during the recation

C.

As, 24 g of oxygen has been utilised during the recation and 29 g of oxygen was supplied therefore amount of oxygen gas left is (29-24) = 5g