Math, asked by Lexiv, 3 months ago

(3i)/(-2-2i) in standard form show work

Answers

Answered by varadad25
3

Answer:

The given complex number in standard form is

\displaystyle{\boxed{\red{\sf\:-\:\dfrac{3}{4}\:-\:\dfrac{3i}{4}}}}

Step-by-step-explanation:

We have given a complex number.

We have to express it in standard form.

The given complex number is

\displaystyle{\sf\:\dfrac{3i}{-\:2\:-\:2i}}

\displaystyle{\implies\sf\:\dfrac{3i}{-\:2\:-\:2i}\:\times\:\dfrac{-\:2\:+\:2i}{-\:2\:+\:2i}}

\displaystyle{\implies\sf\:\dfrac{3i\:(\:-\:2\:+\:2i\:)}{(\:-\:2\:-\:2i\:)\:(\:-\:2\:+\:2i\:)}}

\displaystyle{\implies\sf\:\dfrac{-\:6i\:+\:6i^2}{2^2\:-\:(\:2i\:)^2}}

\displaystyle{\implies\sf\:\dfrac{-\:6i\:+\:6\:\times\:(\:-\:1\:)}{4\:-\:2^2\:\times\:i^2}\:\qquad\cdots[\:\because\:i^2\:=\:-\:1\:]}

\displaystyle{\implies\sf\:\dfrac{-\:6i\:-\:6}{4\:-\:4\:\times\:(\:-\:1\:)}}

\displaystyle{\implies\sf\:\dfrac{-\:6i\:-\:6}{4\:-\:(\:-\:4\:)}}

\displaystyle{\implies\sf\:\dfrac{-\:6i\:-\:6}{4\:+\:4}}

\displaystyle{\implies\sf\:\dfrac{-\:6i\:-\:6}{8}}

\displaystyle{\implies\sf\:-\:\dfrac{\cancel{6}}{\cancel{8}}\:-\:\dfrac{\cancel{6}\:i}{\cancel{8}}}

\displaystyle{\implies\underline{\boxed{\red{\sf\:-\:\dfrac{3}{4}\:-\:\dfrac{3i}{4}}}}}

Answered by XxitzZBrainlyStarxX
55

Question:-

\sf\red{ \frac{3i}{ - 2 - 2i} } \: \sf{in \: standard \: form.}

Given:-

  • We have given a complex number.

To Find:-

  • We have to express it in standard form.

Solution:-

The given complex number is

\longmapsto\tt\sf \:  \frac{3i}{ - 2 - 2i}

  • Standard form = a + ib

 = \sf \:  \frac{3i}{ - 2 - 2i}  =  \frac{ - 3}{2 + 2i}

\sf =  \frac{ - 3i(2 - 2i)}{(2 + 2i)(2 - 2i)}

\sf =  \frac{ - 6i + 6i {}^{2} }{2 {}^{2}  - (2i) {}^{2} }

\sf =  \frac{ - 6i + 6i {}^{2} }{4 + 4}

\sf =  \frac{ - 6i - 6}{8}

\sf{i {}^{2}  = 1}

\sf (2i) {}^{2}  =  - 4

\sf \frac{ - 6i - 6}{8}  =  \frac{ - 6}{8} -  \frac{6i}{8} =   \sf \frac{ - 3}{4}  -  \frac{3i}{4}

\sf a =  \frac{ - 3}{4} ,b =  \frac{ - 3i}{4}

Answer:-

The given complex number in the standard form is

\sf\huge\mathfrak\red{ \frac{ - 3}{4} -  \frac{3i}{4}  }

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