Question

3identical point charges +micro coulum each are are placed at the 3corners A,BNd C respectively of a square ABCD of side 0.1m.calculate the result force acting in the charge at B

Answer 1

Answer:

Let F

1

and F

2

exerted by the charge placed at A and B point of the equilateral triangle on C point as shown in the figure

F

1

=

r

2

Kq

A

q

c

=

(.3)

2

9×10

9

×3×10

−9

×2×10

−9

=6×10

−7

F

2

=

r

2

Kq

B

q

c

=

(.3)

2

9×10

9

×(−3)×10

−9

×2×10

−9

=−6×10

−7

both F

1

and F

2

make angle of 120^0 between each other

resultant of F

1

and F

2

is F

⇒F

2

=F

1

2

+F

2

2

+F

1

F

2

cosθ

⇒(6×10

−7

)

2

+(−6×10

−7

)

2

+2×6×10

−7

×(−6)×10

−7

cos120

0

⇒(36+36−36)×10

−14

=36×10

−14

⇒F=6×10

−7

N