3K-1 , K , K+3 are in A.P. , then find the value of K.
Answers
Answered by
4
hey mate
here is your answer
2t2=t1+t3
2k=3k-1+k+3
2k=4k+2
-2k=2
k=-1(answer)
here is your answer
2t2=t1+t3
2k=3k-1+k+3
2k=4k+2
-2k=2
k=-1(answer)
Anonymous:
welcome
Answered by
1
2(k)=3k-1 + k+3
2k = 4k+2
2k= -2
k=-1
2k = 4k+2
2k= -2
k=-1
Similar questions