(3k+1)x^+2(k+1)x+k=0 find the value of k
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3kx+x+2kx+2x+k=0
5kx+3x+k=0
f (x)=5k+3+k
f (1)=5k+3+k
0 =6k+3
-3=6k
k=-1/2
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