Question

3k^2-3=3k+3 find k . pls ans fast​

Answer 1

Answer:

k= -1 or k=2

Step-by-step explanation:

3k²-3k-6=0

divide by 3 you get

k²-k-2=0

do factorisation

(k-2)(k+1)=0

hence k= -1 or k=2

Answer 2

Answer:

The value of is k = -1, 2

Step-by-step explanation:

$3 {k}^{2} - 3 = 3k + 3 \\ = > 3 {k}^{2} - 3 - 3k - 3 = 0 \\ = > 3 {k}^{2} - 3k - 6 = 0 \\ = > 3 {k}^{2} - (6 - 3)k - 6 = 0 \\ = > 3 {k}^{2} - 6k + 3k - 6 = 0 \\ = > 3k(k - 2) + 3(k - 2) = 0 \\ = > (k - 2)(3k + 3) = 0 \\ therefore \\ k - 2 = 0 = > k = 2 \\ or \\ 3k + 3 = 0 \\ = > 3k = - 3 \\ = > k = - \frac{3}{ 3} \\ = > k = - 1$