Question

3k+5\4k-3=4\9 ꜱᴏʟᴠᴇ ᴀɴᴅ verify​

Answer 1

$\frac{3k+5}{4k-3} = \frac{4}{9} \\4(4k-3) = 9(3k+5)\\16k - 12 = 27k + 45\\27k-16k = -45-12\\11k = -57\\k = -57/11$

Verification:

$\frac{3*\frac{-57}{11} + 5}{4*\frac{-57}{11} - 3} = \frac{4}{9}\\\\\frac{\frac{-171}{11} + 5}{\frac{-228}{11} - 3} = \frac{4}{9}\\\\\frac{\frac{-116}{11}}{\frac{-195}{11}} = \frac{4}{9}\\\\\frac{116}{195} = \frac{4}{9}\\\\\frac{4}{9} = \frac{4}{9}$

LHS =RHS

Hence Verified