Question

3kx - 5y =20 and 8x-6ky=40 . Find the value of k if exist for which thelines are parallel.

Answer 1

Step-by-step explanation:

........PLEASE MARK AS BRAINLIEST........

FOR lines to be parallel....

a1/a2=b1/b2≠c1/c2

Here we will compare a1/a2=b1/b2

(a1=3k, a2=8 ),(c1=20, c2=40) ,(b1=-5 ,b2=-6k)

3k/8=-5/-6k

3k×-6k=-5×8

-18k²=-40

k²=40/18

k²= 20/9

k=2√5/3