Question

3log2+1/3log 27-log 4=log x find x​

Answer 1

Answer:

3log2+

3

1

log27−log4=logx

[∵logm

n

=nlogm]

Therefore

⇒log2

3

+log27

3

1

−log4=logx

⇒log8+log3−log4=logx

[∵logm+logn=log(m×n)]

Therefore

⇒log(8×3)−log4=logx

⇒log24−log4=logx

[∵logm−logn=log(

n

m

)]

Therefore

⇒log(

4

24

)=logx

⇒log6=logx

Now we take anti logarithm both side

x=6