Question

3log2 - 3log3 + log12 - log4 +3log5
Evaluate this.

Answer 1

3log2-3log3+log12-log4+5log5

= log8-log27+log12-log4+log125

= log$\frac{8*12*125}{27*4}$

= log$\frac{1000}{9}$

= log1000-log9

= 3-2log3

HOPE IT HELPS!!

Answer 2

Answer:

here is your answer

Hope this will help you

Plz make me brainliest