Question

3log36/25 + log(6/27)^3 -2log(16/125) is equal to

Answer 1

hope this helps you ☺☺

Answer 2

Answer:

$3log\frac{36}{25} +log(\frac{6}{27}) ^{3} -2log\frac{16}{125}$ is equal to log 2

Step-by-step explanation:

Given equation:

$3log36/25 + log(6/27)^3 -2log(16/125)$

$=log(\frac{36}{25} )^{3} + log(\frac{6}{27} )^{3} -log(\frac{16}{125})^{2}$

$=log((\frac{36}{25} )(\frac{36}{25} )(\frac{36}{25})(\frac{6}{27})(\frac{6}{27})(\frac{125}{16})(\frac{125}{16}))$

$=log2$

Hence the equation equals log 2