3log4+2log5-1/3log64-1/2log16=2
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3 log 4+ 2 log 5 -1/3 log 64-1/2 log 16=2
log (4)³+ log (5)²- log (64)1/³ - log (16)1/²=2
log 64+log 25- log 4- log 4=2
log[(64*25)/(4*4)]=log 100
∴ log 100=log 100
∴3 log 4+ 2 log 5 -1/3 log 64-1/2 log 16=2
log (4)³+ log (5)²- log (64)1/³ - log (16)1/²=2
log 64+log 25- log 4- log 4=2
log[(64*25)/(4*4)]=log 100
∴ log 100=log 100
∴3 log 4+ 2 log 5 -1/3 log 64-1/2 log 16=2
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