Question

3log5-log50+2log2+1.express as a single term.

Answer 1

We know that

• logA + logB = logAB

• logA - logB = log$\frac{A}{B}$  
• nlogA= log$A^{n}$      
• log10 = 1

Applying these properties,

3log5-log50+2log2+1

= log5³ -log50 + log2² + log10

= log$\frac{125*4*10}{50}$

= log100

= log10²

= 2log10

= 2

HOPE IT HELPS !!