Question

3log7-2log5=log343/25

Answer 1

3log7=log7cube=log343
log5square=log25
logA-logB=logA/B
therefore log343/25

Answer 2

Hi friend,

LHS = 3㏒7 - 2㏒5
= ㏒7³ - ㏒5²
= ㏒343 - ㏒25
{㏒M - ㏒N = ㏒ $\frac{M}{N}$ }
= ㏒ $\frac{343}{25}$
= RHS

∴3㏒7 - 2㏒5 = ㏒ $\frac{343}{25}$