Math, asked by rohanmunot24, 9 months ago

(3logx - 2logx^2)+(4logx^2 - 3logx^3)

Answers

Answered by amittiwari2577

0

Answer:

(3logx-4logx) + (8logx - 9logx) = -logx-logx=-2logx

= log(1/x^2)

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