Question

3m^2+2m-7=0 solve using formula

Answer 1

Hey dear !!


Here is yr answer
.................................................................................


3m² + 2m -7 = 0

3m² + ( 7 +(-3) )m + 7 × -3 = 0


it is in the form of x²+(a+b)x+ab = (x+a) (x+b)


( 3m +7) (3m-7)


Hope it hlpz...

Answer 2

Answer:

$\frac{-1\ +\sqrt{22} }{3}, \frac{-1\ -\ \sqrt{22} }{3}$

Step-by-step explanation:

In the question

The given equation is

$3m^{2}\ +\ 2m\ -\ 7 = 0$

a = 3  b = 2  c = -7

we know that, quadratic formula,m = $\frac{-b\±\ \sqrt{b^{2}\ -\ 4ac }}{2a}$

$= \frac{-2\±\ \sqrt{2^{2}\ -\ 4\times3\times(-7) }}{2\times3}$

$= \frac{-2\±\ \sqrt{4\ +\ 84}}{6}$

$\frac{-2\±\ \sqrt{88}}{6}$

$\frac{-2\±\ \sqrt{4\times22}}{6}$

$\frac{-2\±\ 2\sqrt{22} }{6}$

$=2\frac{(-1\±\ \sqrt{22}) }{6}$

$=\frac{-1\±\ \sqrt{22} }{3}$

∴ $m = \frac{-1\ +\ \sqrt{22} }{3}, \frac{-1\ -\ \sqrt{22} }{3}$