Math, asked by gitte2007gitte, 18 hours ago

3m+2n=18 simultaneously​

Answers

Answered by ahmadhawai24
0

Answer:

Let 4m+3n=18 --- (1)

and 3m−2n=5 --- (2)

Multiplying the first equation by 2 , we get 8m+6n=36 -- (3)

Multiplying the second equation by 3 , we get 9m−6n=15 -- (4)

Adding equations 3, and 4 , we get

17m=51

=>m=3

Now, putting m=3 in equation  1 we get, 12+3n=18

=>3n=6

=>n=2

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