Math, asked by saniyammullani5, 5 months ago

3m-4n=7
5m+6n=3
solve this question by elimanation method
plzzzzz give me fast answer

Answers

Answered by monabhardwaj656
1

Step-by-step explanation:

multiply by 3 in equation 1 -

9m-12n= 21

multiply by 2 in eqation 2 -

10m+ 12n= 6

by elimination method-

10m+12n=6

9m-12n= 21

add-

19m=27

m=27/19

put the value of m in eqation 2

5m+6n=3

5.27/19+6n=3

135/19+6n= 3

7.10+6n=3

6n= 3-7.10

n=-4.1/6

n=0.68

i think its right because i do it first time elimination method so....

agar ye wrong h to sorry guys

Answered by Anonymous
1

Answer:

m = 27 / 19, n = - 13 / 19

Step-by-step explanation:

3m - 4n = 7 -----> eq 1.

5m + 6n = 3 -----> eq 2.

eq 1. × 3,

9m - 12n = 21

eq 2. × 2,

10m + 12n = 6

9m - 12n = 21

10m + 12n = 6

___________

19 m = 27

m = 27 / 19 -----> eq 3.

subs eq 3 in eq 1,

( 81 / 19 ) - 4n = 7

( 81 / 19 ) - 7 / 1 = 4n

( 81 / 19 ) - 133 / 19 = 4n

- 52 / 19 = 4n

n = - 52 / 19 × 4

n = - 13 / 19

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