Question

3m longer than its width the flowerbed have an area of 70m2

Answer 1

$\underline{ \pink{ Dimensions \: of \: a \: Rectangular \: flower \: bed : }}$

$Let \: the \: width (w) = x \: m$

$and \: Length (l) = ( x + 3 ) \:m$

$Area \: of \: the \: flower \:bed = 70 \:m^{2}$

$\implies l \times w = 70 \:m^{2}$

$\implies (x + 3) \times x = 70$

$\implies x^{2} + 3x - 70 = 0$

/* Splitting the middle term,we get */

$\implies x^{2} + 10x - 7x - 70 = 0$

$\implies x( x + 10 ) - 7( x + 10 ) = 0$

$\implies ( x + 10 ) ( x - 7 ) = 0$

$\implies x + 10 = 0 \:Or \: x - 7 = 0$

$\implies x = -10 \:Or \: x = 7$

/* x should not be negative */

Therefore.,

$\red{ Width } \green { = 7 \: m }$

$\red{ Length } \\= x + 3 \\= 7 + 3 \\\green { = 10 \:m }$

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Answer 2

Answer:

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