Math, asked by khushisirowa123, 1 year ago

(3m - n)^2- (m - 2n)^2 factorize it​

Answers

Answered by Anonymous
6

Step-by-step explanation:

(3m-n)² - (m-2n)²

(3m-n+m-2n)(3m-n-m+2n)

(4m-3n)(2m+n)

8m²+4mn-6mn-3n²

8m² - 2mn - 3n²

Answered by spandan98
12

Answer:

(4m-3n)(2m+n)

Step-by-step explanation:

(3m-n)^2 -(m-2n)^2

We know a formula,(if you don't know the formula search in the net)

a^2-b^2= (a+b)(a-b)

therefore

(3m-n)^2-(m-2n)^2

=(3m-n+m-2n)(3m-n-m+2n)

=(4m-3n)(2m+n)

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