Math, asked by sunitkaurraysikh, 2 months ago

3m square-11m+8 solve ​

Answers

Answered by piyush20548
0

Answer:

3m

2

−11m+6

Factor the expression by grouping. First, the expression needs to be rewritten as 3m

2

+am+bm+6. To find a and b, set up a system to be solved.

a+b=−11

ab=3×6=18

Since ab is positive, a and b have the same sign. Since a+b is negative, a and b are both negative. List all such integer pairs that give product 18.

−1,−18

−2,−9

−3,−6

Calculate the sum for each pair.

−1−18=−19

−2−9=−11

−3−6=−9

The solution is the pair that gives sum −11.

a=−9

b=−2

Rewrite 3m

2

−11m+6 as (3m

2

−9m)+(−2m+6).

(3m

2

−9m)+(−2m+6)

Factor out 3m in the first and −2 in the second group.

3m(m−3)−2(m−3)

Factor out common term m−3 by using distributive property.

(m−3)(3m−2)

Answered by matthewgarrett
1

Answer: m = 5.4

Step- by- step explanation.

3 (m-2)-5=8-2 (m-4)

Simplifying

3(m + -2) + -5 = 8 + -2(m + -4)

Reorder the terms:

3(-2 + m) + -5 = 8 + -2(m + -4)

(-2 * 3 + m * 3) + -5 = 8 + -2(m + -4)

(-6 + 3m) + -5 = 8 + -2(m + -4)

Reorder the terms:

-6 + -5 + 3m = 8 + -2(m + -4)

Combine like terms: -6 + -5 = -11

-11 + 3m = 8 + -2(m + -4)

Reorder the terms:

-11 + 3m = 8 + -2(-4 + m)

-11 + 3m = 8 + (-4 * -2 + m * -2)

-11 + 3m = 8 + (8 + -2m)

Combine like terms: 8 + 8 = 16

-11 + 3m = 16 + -2m

Solving

-11 + 3m = 16 + -2m

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '2m' to each side of the equation.

-11 + 3m + 2m = 16 + -2m + 2m

Combine like terms: 3m + 2m = 5m

-11 + 5m = 16 + -2m + 2m

Combine like terms: -2m + 2m = 0

-11 + 5m = 16 + 0

-11 + 5m = 16

Add '11' to each side of the equation.

-11 + 11 + 5m = 16 + 11

Combine like terms: -11 + 11 = 0

0 + 5m = 16 + 11

5m = 16 + 11

Combine like terms: 16 + 11 = 27

5m = 27

Divide each side by '5'.

m = 5.4

Simplifying

m = 5.4

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