3m²+2m-7=0
Solve using this formula:-
x= -b+-√b²-4ac/2a
Answers
Answered by
16
Hii ☺ !!
3m² + 2m - 7 = 0
Here,
a = 3 , b = 2 and c = -7
Therefore,
Discriminant ( D ) = b² - 4ac
Discriminant ( D ) = (2)² - 4 × 3 × -7
Discriminant ( D ) = 88
So,
√D = √88 = √2×2 × 2 ×11 = 2√22 .
Therefore,
Roots of the given quadratic equation = -b + √d / 2a or - b - √d / 2a
=> -2 + 2√22 / 2•3 , -2 - 2√22/2•3
=> -2+ 2√22 / 6 , - 2- 2√22/6
=> -2 ( 1 - √22 / 6 ) , - 2 ( 1 + √22 ) / 6
=> 1 - √22/3 , 1 + √22 /3.
Hence,
( 1 - √22/3) and ( 1 + √22/3) are the two zeroes of the given quadratic equation.
3m² + 2m - 7 = 0
Here,
a = 3 , b = 2 and c = -7
Therefore,
Discriminant ( D ) = b² - 4ac
Discriminant ( D ) = (2)² - 4 × 3 × -7
Discriminant ( D ) = 88
So,
√D = √88 = √2×2 × 2 ×11 = 2√22 .
Therefore,
Roots of the given quadratic equation = -b + √d / 2a or - b - √d / 2a
=> -2 + 2√22 / 2•3 , -2 - 2√22/2•3
=> -2+ 2√22 / 6 , - 2- 2√22/6
=> -2 ( 1 - √22 / 6 ) , - 2 ( 1 + √22 ) / 6
=> 1 - √22/3 , 1 + √22 /3.
Hence,
( 1 - √22/3) and ( 1 + √22/3) are the two zeroes of the given quadratic equation.
aakashvishwakarma58:
nice sis.
Answered by
3
a=3,b=2,c=-7
now put value in formula
(i)x=(-2+root -88)/6
=(-2+2 root 22)/6
=(-1 +root 22)/3
similarly _
(ii)x=(-1-root 22)/3
now put value in formula
(i)x=(-2+root -88)/6
=(-2+2 root 22)/6
=(-1 +root 22)/3
similarly _
(ii)x=(-1-root 22)/3
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